-72x^2+72x+8=0

Solution for -72x^2+72x+8=0 equation:

-72x^2+72x+8=0

a = -72; b = 72; c = +8;
Δ = b2-4ac
Δ = 722-4·(-72)·8
Δ = 7488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7488}=\sqrt{576*13}=\sqrt{576}*\sqrt{13}=24\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-24\sqrt{13}}{2*-72}=\frac{-72-24\sqrt{13}}{-144}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+24\sqrt{13}}{2*-72}=\frac{-72+24\sqrt{13}}{-144}
$